Question

On completing a work john mark journey at a total of 841$ how much should join be paid john and mark together complete 11/29 of the work jimmy and mark together completed 19 by 29th of the work

Answer 1

Answer:

It seems there is some problem with this question.

Let the distance between A and B is D km.  As Paul is faster, take the speeds of Jake and Paul are s and 3s kmph.

As the speeds are in the ratio of 1 : 3, times taken by them should be 3 : 1.  Take the times taken by them are 3x , x. But We know that 3x - x = 2 hour 15 min. So 2x = 9/4 hours, x = 9/8 hours. So time taken by the slower one (Jake) takes 3x time = 3 x 9/8 = 27/8 hours = 202.5 minutes.

(Or)

Take Jake speed = j and Paul = p kmph.

Now given that Dj−Dp = 2 hr 15  min = 214 hrs =  9/4 hrs

Also both of them together covered D distance in 2 hours.  So Dj+Dp=2

Adding these two equations will give us 2Dj=94+2=174 = 4 hours 15 minutes.

So in the above problem, some part is redundant.