Question

On converting 308 K, 329 K and 391 K to Celsius scale, the correct sequence of temperatures will be (a) 33°C, 56°C and 118°C
(b) 35°C, 56°C and 119°C
(c) 35°C, 56°C and 118°C
(d) 56°, 119°C and 35°C

Answer 1

(c) 35°C, 56°C and 118°C

Explanation:

We are given three kelvin temperatures.We are supposed to convert them into celsius scale and arrange them in order.

The relation between kelvin and celsius scale is,

$\frac{K-273}{100}=\frac{C}{100}$

The kelvin temperatures given are 308 K, 329 K and 391 K .

So let us convert the three kelvin temperatures,

$\frac{308-273}{100}=\frac{C_{1} }{100}\\  \\C_{1}=35\\ \\\frac{329-273}{100}=\frac{C_{2} }{100}\\  \\C_{2}=56\\\\\frac{391-273}{100}=\frac{C_{3} }{100}\\  \\C_{3}=118$

So by arranging them in increasing order we get, 35°C, 56°C and 118°C

Answer 2

Answer is Option C

Explanation:

Subtraction of 273 from the Kelvin Value gives Value in Celsius

We know that,

1K = 1C + 273

or we can say

1C = K - 273 which say that on subtraction of 273 from Kelvin, we get the value of temperature in Celsius.

Applying the above rule we get the solution as under -  

• i.) 308 K  

C = 308 - 273

= 35° C

• ii.) 329 K

C = 329 - 273  

= 56° C

• iii.) 391 K

C = 391 - 273

= 118°C