Physics, asked by TheLegend0353, 4 days ago

On December 11, 2006, Jupiter was 944 million kilometers from Earth and had an angular diameter of 31.2 arcseconds. From this information, calculate the actual diameter of Jupiter in kilometers.

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Answers

Answered by selvakrish135
1

Jupiter has a mean radius of 43,440.7 miles (69,911 kilometers), about a tenth that of the sun. However, its rapid rotation — it spins once every 9.8 hours — causes it to bulge at the equator, where the diameter is 88,846 miles (142,984 km). In contrast, the diameter at the poles is only 83,082 miles (133,708 km). This stretched shape is known as an oblate spheroid.

If you were to walk around the equator of Jupiter, you would travel 272,946 miles (439,264 km), over 10 times the distance around Earth's center line.

Answered by pavanisimha1
1

Answer:

On December 11, 2006, Jupiter was 944 million kilometers from Earth and had an angular diameter of 31.2 arcseconds. From this information, calculate the actual diameter of Jupiter in kilometers.

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