On decreasing temperature of following system at equilibrium CO2() -
CO2(g),AH = positive
(A) There is no effect on the equilibrium state
(B) More CO2 gas is formed
(C) More solid CO2 is obtained
(D) None of above
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Chemical equilibrium is the state in which both reactant and product are present in concentrations which have no further tendency to change with time, so there is no observable change in the properties of the system.
Change in temperature, only effects the reaction when △ng\triangle ng △ng varies.
So, △ng=\triangle ng =△ng= number of moles of product-number of a mole of reactant.
Since,
CO2(s)⇌CO2(g){ CO }_{ 2 }(s)\rightleftharpoons { CO }_{ 2 }(g)CO2(s)⇌CO2(g), there is no change in △ng\triangle ng △ng Hence, on decreasing temperature there is no effect on the equilibrium state.
Hence, answer is (D) None of the above.
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