Math, asked by ItzMayurBhai01, 3 months ago

on decreasing the radius of circle by 30% it's area is decreased by

30%

60%

45%

none​

Answers

Answered by Anonymous
25

sorry dude....your all options are wrong.......right answer is 51%

decreased \: area \:  = total \: area - remained \: area \\  = \pi {r}^{2}  - \pi {r |2| }^{2}  \\  \\  = \pi({ \frac{100}{100})}^{2}  -  \pi{\frac{70}{100}}^{2}  \\  = 1 - 0.49 \\  = 0.51 \\  = 51\%

hope it will help you.....:)

Answered by Anonymous
4

let the radius of circle be R

Area of the circle= 3.14 * R^2

Now, radius is decreased by 30%

New radius of circle would be 0.7R

Hence,

New Area= 3.14*(0.7R)^2

New Area= 0.49 * 3.14*R^2

Therefore, New area of the circle would be 51% less than that of original one.

so, option D is correct..

hope it helps you ☺☺

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