Question

On dipping a capillary of radius 'r' in water, water rises upto a height h and potential energy of water is u1. If a capillary of radius 2r is dipped in water, then the potential energy is u2. The ratio u1u2 is

Answer 1

As,

u ∝ h ^ 2 r ^ 2

u1 / u2 = h1 ^2 r1 ^2 / h2 ^ 2 r2 ^ 2

So ,

u1 : u2 = 1 : 1

Density (rho) x V = T x 2  π r

P. E ( u ). = rho x g x h

u1 / u2 = 2