Question

On dissolving 28 g of koh in water to form 1 liter of the solution the temperature rises by 6.89°c ,(k=39,h=1,o=16) ,what is the molar heat of the solution of koh ?

Answer 1

Answer:

Explanation:

m = 28 g, dT = 6.89 degree celcius

Here, Molar mass of KOH = (39+1+16) g = 56 g

Now, mole no, n = 28/56 = 0.5

Heat capacity of KOH = 65.87 J/mol·K

Now, q = n * Cg * dT = 0.5*65.87*6.89 = 226.92 J