Math, asked by ros108582, 5 hours ago

On dividing 10x⁴ +17x³

-62x²+30x-3 by 2x²+7x-1 , what will

be the quotient(Q) and remainder(R)​

Answers

Answered by stutigarg903
0

Answer:

Q is 5x^2 - 9x +3

R is 0

Step-by-step explanation:

after dividing we get this answer

hope it will help u .

Answered by Anonymous
3

Quotient=5x²-9x+3 and Remainder=0 ☑

Step-by-step explanation:

2x²+7x-1)10x⁴+17x³-62x²+30x-3(5x²-9x+3

10x⁴+35x³-5x²

- - +

______________

-18x³-57x²+30x

-18x³-63x²+9x

+ + -

_______________

6x²+21x-3

6x²+21x-3

- - +

____________

✅Hence, the Quotient is 5x²-9x+3 and remainder is 0.

Proof⤵

⚫Using formula

Dividend= Quotient× Divisor+Remainder

➡10x²+17x³-62x²+30x-3 =( 5x²-9x+3) ×(2x²+7x-1) +0

➡10x²+17x³-62x²+30x-3 =2x²( 5x²-9x+3)+7x( 5x²-9x+3)-1( 5x²-9x+3)+0

➡10x²+17x³-62x²+30x-3=10x⁴-18x³+6x²+35x³-63x²+21x-5x²+9x-3+0

➡10x²+17x³-62x²+30x-3=10x⁴-18x³+35x³+6x²-63x²-5x²+21x+9x-3

➡10x²+17x³-62x²+30x-3=10x²+17x³-62x²+30x-3

LHS = RHS

Hence proofed.

Hope this is helpful to you!

Similar questions