On dividing 10x⁴ +17x³
-62x²+30x-3 by 2x²+7x-1 , what will
be the quotient(Q) and remainder(R)
Answers
Answer:
Q is 5x^2 - 9x +3
R is 0
Step-by-step explanation:
after dividing we get this answer
hope it will help u .
Quotient=5x²-9x+3 and Remainder=0 ☑
Step-by-step explanation:
2x²+7x-1)10x⁴+17x³-62x²+30x-3(5x²-9x+3
10x⁴+35x³-5x²
- - +
______________
-18x³-57x²+30x
-18x³-63x²+9x
+ + -
_______________
6x²+21x-3
6x²+21x-3
- - +
____________
✅Hence, the Quotient is 5x²-9x+3 and remainder is 0.
Proof⤵
⚫Using formula
Dividend= Quotient× Divisor+Remainder
➡10x²+17x³-62x²+30x-3 =( 5x²-9x+3) ×(2x²+7x-1) +0
➡10x²+17x³-62x²+30x-3 =2x²( 5x²-9x+3)+7x( 5x²-9x+3)-1( 5x²-9x+3)+0
➡10x²+17x³-62x²+30x-3=10x⁴-18x³+6x²+35x³-63x²+21x-5x²+9x-3+0
➡10x²+17x³-62x²+30x-3=10x⁴-18x³+35x³+6x²-63x²-5x²+21x+9x-3
➡10x²+17x³-62x²+30x-3=10x²+17x³-62x²+30x-3
LHS = RHS
✔Hence proofed.
Hope this is helpful to you!