Question

On dividing 200 rupees between A and B such that twice of a share is less than three time B share
by 200 find B share.​

Answer 1

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

On dividing Rs.200 between A and B such that twice of A share is less than three times B share by 200.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The B share.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the B share be r

Let the A share be (200 - r)

A/q

$\longrightarrow\sf{2\times A\:share - (3\times B \:share -200)=0}$

We putting the value of that we supposed,we get;

$\longrightarrow\sf{2\times (200-r)-(3\times r-200)=0}\\\\\\\longrightarrow\sf{400-2r-3r+200=0}\\\\\\\longrightarrow\sf{-5r+400+200=0}\\\\\\\longrightarrow\sf{-5r+600=0}\\\\\\\longrightarrow\sf{-5r=-600}\\\\\\\longrightarrow\sf{r=\cancel{\dfrac{-600}{-5} }}\\\\\\\longrightarrow\sf{\pink{r=Rs.120}}$

Thus;

The B share is Rs.120 .

Answer 2

$\huge\sf{Answer:}$

According to the question:

⇏ On dividing Rs.200 between A and B such that twice of A share is less than three times B share by 200.

Find:

⇏ What is the share of B.

Calculations:

⇏ Let us assume 'x' as B's share and (200-x) as A's share.

⇏ $\sf 2 \times (200 - x) - (3 \times (x) - 200) = 0$

Adding values to the equation, we get:

⇏ $\sf 2 \times (200 - x) - (3 \times x - 200)=0$

⇏ $\sf (400 - 2x) - (3x+200)=0$

⇏ $\sf -5x +(400+200)=0$

⇏ $\sf -5x +600 =0$

⇏ $\sf -5x= - 600$

⇏ $\sf x= \dfrac{ - 600}{ - 5}$

⇏ ${\sf{\boxed{\sf{ x = 120}}}}$

Therefore, 120 is the share of B.