On dividing 2272 as well as 875 by a 3-digit number N, we get the same remainder.
The sum of the digits of N is
(1) 10
(2) 11
(3) 12
(4) 13
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Answer:
(2272 - 875) = 1397, is exactly divisible by N. The required 3-digit number is 127, the sum of whose digits is 10
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