on dividing 2272 as well as 875 by a 3-digit number N,we get the same remainder.The sum of the digits of N is
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Sum of digit 1+2+7=10
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On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. ... Clearly, (2272 - 875) = 1397, is exactly divisible by N. Now, 1397 = 11 x 127. The required 3-digit number is 127, the sum of whose digits is 10.
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