On dividing 2272 as well as 875 by a 3-digit number N, we get the same remainder. The sum of the digits of Nis (1) 10 2) 11 3 12 (43) 13
Answers
Answered by
0
Answer:
So, we will first find the difference between the given numbers i.e. 2272 and 875. 1397 will be divisible by three digit number i.e. \[N\]. ... The sum of the digits of \[N\] \[ = 1 + 2 + 7 = 10\]. Hence, the correct option is option A.
Answered by
0
Answer:
Step-by-step explanation:
N
1
=2272;N
2
=875
When N
1
and N
2
divide by N give remainder r
Then N
1
−r,N
2
−r is also divisible by N
N
(2272−r)−(875−r)
N→11,127
1397
∴N=127
Sum of digit =1+2+7=10
Similar questions