On dividing 3x^3-2x^2+5x+ 5 by the polynomial p (x),the quotient and remainder are x^2-x+2and -7. Find p(x)
Payal001:
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dividend=divisor*question+remainder
3x^3-2x^2+5x-5=(3x+1)(x^2-x+2)+(-7) divisor
3x^3-2x^2+5x-5=(3x+1)(x^2-x+2)+(-7) divisor
Answered by
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Answer:
3x+1
Step-by-step explanation:
3x^3-2x^2+5x-5=p[x] . [x^2-x+2]-7
3x^3-2x^2+5x+2 / x^2-x+2=p[x]
∵ remainder is 0,hence given polynomial is completely divisible by p[x].
∴p[x]=3x+1
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