On dividing 3x^3 +4x^2+5x-13 by a polynomial g(x) the quotient nd remainder are 3x+10and 16x-43respectively. Find g(x)
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Hi!
HERE'S YOUR ANSWER>>>>>>>>>>>>>>>>>>
p(x)=g(x)×q(x)+r(x)
3x^3+4x^2+5x-13=g(x)×(3x+10)+16x-43
3x^3+4x^2+5x-13-16x+43=g(x)×(3x+10)
3x^3+4x^2-11x+30=g(x)×(3x+10)
3x^3+4x^2-11x+30/3x+10=g(x)
_______________
3x+10)3x^3+4x^2-11x+30( x^2-2x+3
3x^3+10x^2
- -
__________________
-6x^2-11x
-6x^2-20x
+ +
__________________
9x+30
9x+30
- -
__________________
0
__________________
=x^2-2x+3
HOPE that this will help you..........
Please mark it as brainliest
HERE'S YOUR ANSWER>>>>>>>>>>>>>>>>>>
p(x)=g(x)×q(x)+r(x)
3x^3+4x^2+5x-13=g(x)×(3x+10)+16x-43
3x^3+4x^2+5x-13-16x+43=g(x)×(3x+10)
3x^3+4x^2-11x+30=g(x)×(3x+10)
3x^3+4x^2-11x+30/3x+10=g(x)
_______________
3x+10)3x^3+4x^2-11x+30( x^2-2x+3
3x^3+10x^2
- -
__________________
-6x^2-11x
-6x^2-20x
+ +
__________________
9x+30
9x+30
- -
__________________
0
__________________
=x^2-2x+3
HOPE that this will help you..........
Please mark it as brainliest
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