On dividing 3x3 - 2x2 + 5x - 5 by a polynomial p(x), the quotient and remainder are x2 - x + 2 and -7 respectively, Find p(x).
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Answered by
49
♧♧HERE IS YOUR ANSWER♧♧
♤♤RULE♤♤
Let, f(x) be any polynomial. On division by p(x), if it gives quotient q(x) and remainder r(x), the relation is :
f(x) = p(x).q(x) + r(x)
♤♤SOLUTION♤♤
Here, we consider :
f(x) = 3x³ - 2x² + 5x - 5
q(x) = x² - x + 2
r(x) = -7
Now, applying the relation f(x) = p(x).q(x) + r(x), we get :
(3x³ - 2x² + 5x - 5) = (x² - x + 2).p(x) - 7
=> (x² - x + 2).p(x) =(3x³ - 2x² + 5x - 5) + 7
=> (x² - x + 2).p(x) = 3x³ - 2x² + 5x + 2
=> (x² - x + 2).p(x) = (x² - x + 2)(3x + 1)
Now, eliminating (x² - x + 2), we get :
p(x) = 3x + 1
◇◇PLANNING◇◇
3x³ - 2x² + 5x + 2
= 3x³ - 3x² + 6x + x² - x + 2
= 3x(x² - x + 2) + 1(x² - x + 2)
= (3x + 1)(x² - x + 2)
⬆HOPE THIS HELPS YOU⬅
♤♤RULE♤♤
Let, f(x) be any polynomial. On division by p(x), if it gives quotient q(x) and remainder r(x), the relation is :
f(x) = p(x).q(x) + r(x)
♤♤SOLUTION♤♤
Here, we consider :
f(x) = 3x³ - 2x² + 5x - 5
q(x) = x² - x + 2
r(x) = -7
Now, applying the relation f(x) = p(x).q(x) + r(x), we get :
(3x³ - 2x² + 5x - 5) = (x² - x + 2).p(x) - 7
=> (x² - x + 2).p(x) =(3x³ - 2x² + 5x - 5) + 7
=> (x² - x + 2).p(x) = 3x³ - 2x² + 5x + 2
=> (x² - x + 2).p(x) = (x² - x + 2)(3x + 1)
Now, eliminating (x² - x + 2), we get :
p(x) = 3x + 1
◇◇PLANNING◇◇
3x³ - 2x² + 5x + 2
= 3x³ - 3x² + 6x + x² - x + 2
= 3x(x² - x + 2) + 1(x² - x + 2)
= (3x + 1)(x² - x + 2)
⬆HOPE THIS HELPS YOU⬅
Answered by
40
I hope it will help you.....
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