On dividing 3x3 + 4x2 + 5x – 13 by a polynomial g(x) the quotient and remainder were 3x +10 and 16x – 43 respectively. Find the polynomial g(x).
Answers
Answered by
1
Answer:
Let g(x) = y
now
divisor * quotient + remainder = dividend
y * (3x+10) + 16x-43 = 3x^3 + 4x² + 5x - 13
y * (3x+10) = 3x^3 + 4x² - 11x + 30
now we can calculate the value of y by dividing
3x^3 + 4x² - 11x +30 from 3x+10
so
y = x² - 2x + 3
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Answered by
0
Answer:
Step-by-step explanation:
et g(x) = y
now
divisor * quotient + remainder = dividend
y * (3x+10) + 16x-43 = 3x^3 + 4x² + 5x - 13
y * (3x+10) = 3x^3 + 4x² - 11x + 30
now we can calculate the value of y by dividing
3x^3 + 4x² - 11x +30 from 3x+10
so
y = x² - 2x + 3
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