on dividing 3x³+4x²+5x-13 by polynomial g(x),the quotient and the remainder are 3x +10 and 16x-43 respectively. find g(x)
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Heya user !!!
Here's the answer you are looking for
Dividend = Divisor × Quotient + Remainder
Here,
3x³+4x²+5x-13 = g(x) × (3x +10) + 16x-43
3x³+4x²+5x-13 - (16x-43) = g(x) × (3x +10)
3x³+4x²+5x-13 - 16x + 43 = g(x) × (3x +10)
3x³ + 4x² - 11x + 30 = g(x) × (3x +10)
So, g(x) = ( 3x³ + 4x² - 11x + 30) / (3x +10)
= x² - 2x + 3
Therefore, g(x) is x² - 2x + 3
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Dividend = Divisor × Quotient + Remainder
Here,
3x³+4x²+5x-13 = g(x) × (3x +10) + 16x-43
3x³+4x²+5x-13 - (16x-43) = g(x) × (3x +10)
3x³+4x²+5x-13 - 16x + 43 = g(x) × (3x +10)
3x³ + 4x² - 11x + 30 = g(x) × (3x +10)
So, g(x) = ( 3x³ + 4x² - 11x + 30) / (3x +10)
= x² - 2x + 3
Therefore, g(x) is x² - 2x + 3
★★ HOPE THAT HELPS ☺️ ★★
uznain:
thank you
no problem :-)
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the answer is in the above picture
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