On dividing a number by 13 we get 1 as remainder. If the quotient is divided by 5 we get 3 as remainder. If this number is divided by 65 what will be the remainder
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let the no. be n
By remainder theorem :-
n=13q+1 -------------1 where q is quotient
also given
q=5t+3 -------------2 where t is quotient when q is divided by 5
put the value of eq 2 in eq 1 we get
n=65t + 40
Therefore 40 is the remainder
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By remainder theorem :-
n=13q+1 -------------1 where q is quotient
also given
q=5t+3 -------------2 where t is quotient when q is divided by 5
put the value of eq 2 in eq 1 we get
n=65t + 40
Therefore 40 is the remainder
hope this helps you
please follow me
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