On dividing a number by 3, 4 and 7, the remainders are 2, 1 and 4 respectively. If the same number is
divided by 84 then the remainder is
(1) 80 (2) 76 (3) 53 (4) None of these
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as the number gives a remainder of 4 when it is divided by 7, then the number must be in the form of (7x +4)
the same gives remainder 1 when it is divided by 4, so the number must be in the form of {4 × (7x +4) +1 }
also, the number when divided by 3 gives remainder 2, this number must be in the form of [3×{4×(7x+4)+1}+2]
= 84x +53
as we get the final number 53 more than a multiple of 84. hence ,if the number is divided by 84
remainder will be 53
the same gives remainder 1 when it is divided by 4, so the number must be in the form of {4 × (7x +4) +1 }
also, the number when divided by 3 gives remainder 2, this number must be in the form of [3×{4×(7x+4)+1}+2]
= 84x +53
as we get the final number 53 more than a multiple of 84. hence ,if the number is divided by 84
remainder will be 53
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