Question

On dividing a number by 4, the remainder is 2. The quotient so obtained when divided by 5, leaves the remainder 3. Now the quotient so obtained when divided by 6, leaves the remainder 5. The last quotient is 7. The number was​

Answer 1

Answer:

1/2/4/3/

I don't know

perfect tokka

Answer 2

Answer:

Start from the last part of the problem. Let Q1 =7. We will call quotients Q2, Q3 and Q4 as we work back.

Q2 when divided by 6 leaves reminder 5 and quotient Q1 =7 => Q2=7*6 + 5 = 47

Q3 when divided by 5, leaves quotient Q2=47 and reminder of 3, so Q3 = 5*47 + 3 = 238

Similarly Q4=238*4 + 2 = 954 is the answer

Step-by-step explanation:

Let the number be n. Then

n =4a+2.

a=5b+3.

b=6*7 +5 =47.

Hence a=5*47 +3 = 238.

Finally n=4*238 +2 = 954.