Question

On dividing a number by 4, the sum of quotient and remainder is 8 and sum of their squares is 34. Find the number.(1) 22(2) 23(3) 24(4) 25
pls solve this question properly


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Answer 1

Answer:

Let the two digit number be 10x+y and number obtained by interchanging the digit =10y+x

As per the first condition,

10x+y=6(x+y)+3

4x−5y=3...(i)

As per the second condition,

10y+x=4(x+y)+9

−3x+6y=9...(ii)

Multiplying equation (i) by 3 and (ii) by 4 and adding them, we get

12x−15y=9

−12x+24y=36

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9y=45

y=5

Substitute y=5 in equation (i)

4x−5×5=3

4x=28

x=7

So, the number =10x+y=10×7+5=75