Math, asked by rameshregu0, 5 days ago

On dividing a number by 8, the quotient is 11 and remainder is 6.Find the number​

Answers

Answered by ChitranjanMahajan
0

The number 94 produces a Quotient of 11 and a Remainder of 6 on division by 8.

Division Parameters :

  • The number or value that is divided is called the "Dividend"
  • The number or value by which the dividend is divided is called the "Divisor"
  • The result in the whole number obtained by dividing the Dividednd by the Divisor is called the Quotient
  • In case, the Dividend is not an exact multiple of the Divisor, the value left is called the Remainder.
  • The relation between them are :

       Dividend = ( Divisor * Quotient ) + Remainder

The values given are :

  • Divisor = 8
  • Quotient = 11
  • Remainder = 6
  • Thus, applying the formula to find the Dividend number :

                Dividend = ( Divisor * Quotient ) + Remainder

                                = ( 8 * 11 ) + 6

                                = 88 + 6

                                = 94

Hence, the required number is 94.

To learn more about Dividend and Divisor, visit

https://brainly.in/question/49423068

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Answered by mathdude500
0

Answer:

 \:\boxed{\bf \:  Required\:number\:is\:94 \: }  \\

Step-by-step explanation:

Given that, on dividing a number by 8, the quotient is 11 and remainder is 6.

Let assume that the required number be x.

So,

When x is divided by 8, the quotient is 11 and remainder is 6

So, we have

\sf \: Dividend = x \\

\sf \: Divisor = 8 \\

\sf \: Quotient = 11 \\

\sf \: Remainder = 6 \\

We know, By Division algorithm,

\sf \: Dividend = Divisor \times Quotient + Remainder \\

On substituting the values, we get

\sf \: x = 8 \times 11 + 6 \\

\sf \: x = 88 + 6 \\

\implies\sf \: x = 94 \\

Hence,

\implies\sf \:\boxed{\bf \:  Required\:number\:is\:94 \: }  \\

\rule{190pt}{2pt}

Additional Information

\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{{More \: identities}}}} \\ \\ \bigstar \: \bf{ {(x + y)}^{2} =  {x}^{2}  + 2xy +  {y}^{2} }\:\\ \\ \bigstar \: \bf{ {(x - y)}^{2}  =  {x}^{2} - 2xy +  {y}^{2} }\:\\ \\ \bigstar \: \bf{ {x}^{2} -  {y}^{2} = (x + y)(x - y)}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{2}  -  {(x - y)}^{2}  = 4xy}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{2}  +  {(x - y)}^{2}  = 2( {x}^{2}  +  {y}^{2})}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{3} =  {x}^{3} +  {y}^{3} + 3xy(x + y)}\:\\ \\ \bigstar \: \bf{ {(x - y)}^{3} =  {x}^{3} -  {y}^{3} - 3xy(x - y) }\:\\ \\ \bigstar \: \bf{ {x}^{3}  +  {y}^{3} = (x + y)( {x}^{2}  - xy +  {y}^{2} )}\: \end{array} }}\end{gathered}\end{gathered}\end{gathered}

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