On dividing a polynomial p(x) by (x+3); which of the following can be a remainder ?
Answers
Answer:
Answer
(i) x−3
x
2
−2)
x
3
−3x
2
+5x−3
x
3
−2x
________________
−3x
2
+7x−3
−3x
2
−6
________________
7x−9
Quotient=x−3
Remainder=7x−9
(ii) x
2
+x−3
x
2
−x+1)
x
4
−3x
2
+4x+5+0x
3
x
4
+x
2
−x
3
______________________
x
3
+4x
2
+4x+5
x
3
−x
2
+x
______________________
−3x
2
+3x+5
−3x
2
+3x−3
______________________
8
Quotient=x
2
+x−3
Remainder=8
(iii) −x
2
−2
2−x
2
)
x
4
+0x
3
+0x
2
−5x+6
x
4
−2x
2
____________________
0x
3
+2x
2
−5x+6
+2x
2
−4
_____________________
−5x+10
Quotient=−x
2
−2
Remainder=−5x+10.