Math, asked by mayabkbhalla5650, 10 months ago

On dividing a polynomial p(x) by x2 - 4, quotient and remainder
found to be x and 3 respectively. The polynomial p(x) is

Answers

Answered by amitnrw
52

Given : a polynomial p(x)  divided by x² - 4 ,  Quotient = x  & remainder = 3

To find : Polynomial p(x)

Solution:

As we know that

p(x) = q(x) . g(x)  + r(x)

where

q(x) = x

g(x) = x² - 4

r(x) = 3

Substituting all known values

p(x) = x . (x² - 4)  + 3

=> p(x) =  x³ - 4x + 3

Polynomial p(x) = x³ - 4x + 3   which on dividing by x² - 4  give Quotient x  & remainder = 3

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Answered by Agastya0606
23

Given: when p(x) / (x² - 4)  we get remainder as 3 and quotient as x   .

To find: polynomial p(x)

Solution:

  • To find the polynomial, we have the formula which states that p(x) can be found out by multiplication of quotient and dividend and then adding it to the remainder.
  • Formula for p(x) is:

        p(x) = ( q(x) x g(x) )  + r(x)

  • Here, q(x) = x, g(x) = x² - 4 and r(x) = 3

  • So to find p(x) lets substitute all the values, we get

        p(x) =( x × (x² - 4) )+ 3

        p(x) =( x³ - 4x )+ 3

Answer:

        So the polynomial obtained is p(x) = x³ - 4x + 3

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