On dividing a positive integer n by 9 , we get 7 as remainder. What will be the remainder if (3n-1) is divided by 9 ?
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let q be the quotient by n is divided by 9
now dividend =divisor ×quotient +remainder
n=9×q+7
n=9q+7
now 3n-1=3×(9q+7 )=27q+21-1=27q+20=27q+18+2
when 3n-1 is divided by 9
when 27q+18+2 is divided by 9
when 9 (3q+2)+2 is divided by 9 the remainder is 2
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