On dividing a positive integer n by 9, we get 7 as remainder. What will
be the remainder if (3n – 1) is divided by 9?
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Answered by
8
Answer:
2
Step-by-step explanation:
⇒n=9q+7.
⇒3n=3(9q+7)=27q+21.
⇒3n−1=27q+21−1=27q+20=9(3q+2)+2.
⇒ Dividing 3n−1 by 9 is equivalent to dividing 9(3q+2)+2 by 9.
Since 9 is a factor of 9(3q+2) and 2<9, the remainder when 9(3q+2)+2 is divided by 9 is 2.
⇒ The remainder when 3n−1 is divided by 9 is 2.
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