On dividing a positive integer n by 9, we get 7 as remainder. What will
be the remainder if (3n-1) is divided by 9?
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So, substituting the values of dividend which is equals to n, divisor which is equals to 9, quotient equals to q and remainder is equals to 7. Make in the form of 9 \[ * \] quotient \[ + \] remainder. Therefore, when (3n-1) is divided by 9, we get the remainder 2.
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n=9q+7⇒3n−1=27q+20
⇒27q+18+2=9(3q+2)+2
>3n−1=9k+2
> Remainder is 2 when 3n−1 is divided by 9.
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