Math, asked by anushka4797, 1 day ago

On dividing a positive integer n by 9, we get 7 as remainder. What will
be the remainder if (3n-1) is divided by 9?

Answers

Answered by pradip201186
1

Answer:

Complete step-by-step answer:

So, substituting the values of dividend which is equals to n, divisor which is equals to 9, quotient equals to q and remainder is equals to 7. Make in the form of 9 \[ * \] quotient \[ + \] remainder. Therefore, when (3n-1) is divided by 9, we get the remainder 2.

Answered by jeridrew051220
1

n=9q+7⇒3n−1=27q+20

⇒27q+18+2=9(3q+2)+2

>3n−1=9k+2

> Remainder is 2 when 3n−1 is divided by 9.

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