on dividing n by 9 we get 7 as remainder . what will be the remainder if 3n-1 was divided by 9
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1
Step-by-step explanation:
According to uclid division lemma
a=bq+r
or
a/q
n=9q+7
3n-1= 3(9q+7) -1
= 27q+21 -1
= 27q+20
if any number divide by 9 then remainder will be 0 to 8
so
here we get remainder = 20
then devide 20 /9
we get 2 as remainder
your anser is 2.
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