On dividing p(4p2 – 16) by 4p( – 2), we get
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2
Answer:
We have,
4p(p−2)
p(4p
2
−16)
Factorising the numerator,
=
4p(p−2)
p[(2p)
2
−4
2
]
=
4(p−2)
(2p−4)(2p+4)
[Using a
2
−b
2
=(a+b)(a−b)]
=
4(p−2)
2(p−2)×2(p+2)
=
4(p−2)
4(p−2)(p+2)
=(p+2)
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