Question

On dividing the polynomial 10x^4 – 6x^3 – 40x^2+ 41x – 5 by the polynomial g (x) , the quotient is 5x – 3 and remainder is 2x + 4. Find the polynomial g(x). I will mark u as the brainliest if u tell it right.

Answer 1

Go through this ,It will help u a lot but please read it carefully and attentively.

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Answer 2

Answer:

let divided = p(x)

let divisor = g(x)

let the quotient = q(x)

let the remainder = r(x)

formula :

Divided = Divisor * quotient + remainder

10 x^4- 6x^3-40x^2+41x-5 = g(x)* 5x-3 + 2x+4

10 x^4- 6x^3-40x^2+41x-5-(2x+4) = g(x)*5x-3

10 x^4- 6x^3-40x^2+39x-1 = g(x)* 5x-3

10 x^4- 6x^3-40x^2+39x-1 / 5x-3 = g(x)

hope this help u