Question

on dividing the polynomial by x²-2 the quotients is found as 2x²+5x-2 and the remainder as -x+14.find the polynomial​

Answer 1

Step-by-step explanation:

p(x) = divisior × quotient + remainder

p(x) = g(x) × q(x) + r(x)

p(x) = ?, g(x) = x² - 2, q(x) = 2x² + 5x - 2, r(x) = -x + 14

p(x) = (x² - 2)(2x² + 5x - 2) + 14 - x

p(x) = 2x⁴ + 5x³ - 2x² - 4x² - 10x + 4 + 14 - x

p(x) = 2x⁴ + 5x³ - 6x² - 11x + 18

Answer 2

Answer:

g(x)=x²-2

q(x)=2x²+5x-2

r(x)=-x+14

p(x)=?

Step-by-step explanation:

Therefore,Divident =Divisor×Question +Remainder

p(x)=g(x)×q(x)+ r(x)

p(x)=(x²-2) (2x²+5x-2) +14-x

p(x) 2x⁴+5x³-2x²-4x²-10x+4+14-x

p(x)=2x⁴+5x³-6x²-11x+18

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