on dividing the polynomial px= x3-3x2+x+2 by a polynomial gx, the quotient qx and remainder rx are x-2 and - 2x+4 respectively find the polynomial gx
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here is your answer......
hope this will help you out
hope this will help you out
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aayushjain1008:
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Hii friend,
P(X) = X³-3X²+X+2
Q(X) = X-2
R(X) = -2X+4
G(X) = ?
By Euclid division lemma,
Dividend = Divisor × Quotient + Remainder
X³-3X²+X+2 = G(X) × (X-2) + (-2X+4)
G(X) = F(X) - R(X)/Q(X)
Now,
F(X) - R(X) = X³-3X²+X+2 - (-2X+4)
= (X³-3X²+3X-2)
Therefore,
G(X) = (X³-3X²+3X-2)/(X-2)
We have to divide (X³-3X²+3X-2) by( X-2), we get G(X) = (X²-X+1).
HENCE,
G(X) = (X²-X+1).
HOPE IT WILL HELP YOU.... :-)
P(X) = X³-3X²+X+2
Q(X) = X-2
R(X) = -2X+4
G(X) = ?
By Euclid division lemma,
Dividend = Divisor × Quotient + Remainder
X³-3X²+X+2 = G(X) × (X-2) + (-2X+4)
G(X) = F(X) - R(X)/Q(X)
Now,
F(X) - R(X) = X³-3X²+X+2 - (-2X+4)
= (X³-3X²+3X-2)
Therefore,
G(X) = (X³-3X²+3X-2)/(X-2)
We have to divide (X³-3X²+3X-2) by( X-2), we get G(X) = (X²-X+1).
HENCE,
G(X) = (X²-X+1).
HOPE IT WILL HELP YOU.... :-)
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