on dividing x^2+5x^2+8x+2 by a polynomial g(x),the quptient and remainder were x^2+4x+3 and x-1 respectively. find g(x).
Answers
Answered by
1
Let p(x)=x^3-8x^2+20x-10.
g(x) be the divisor.
q(x)=x-4. [quotient]
r(x)=6. [remainder]
AS WE KNOW THAT,
Dividend=divisor×quotient+,remainder.
=> p(x)=g(x)×(x-4)+6
=>(x^3-8x^2+20x-10-6)÷(x-4)=g(x)
=>x^2- 4x + 4 = g(x)
Hence,g(x)=x^2- 4x + 4.
Answered by
7
YOUR POLYNOMIAL IS WRONG. THERE MUST BE X³ IN PLACE OF X² .
YOUR POLYNOMIAL IS WRONG. THERE MUST BE X³ IN PLACE OF X² .REFER TO THE ATTACHMENT ❣️
Attachments:
karishofficial:
tq
Similar questions