Question

On dividing x^3 + 3X + 2 by a polynomial g(x) the coefficient and the remainder power x - 2 and 16 respectively find g(X)

Answer 1

ANSWER :

p(x) = x^3 + 3x + 2

q(x) = x - 2

r(x) = 16

We know, Dividend = Divisor × Quotient + Remainder.

x^3 + 3x + 2 = g(x) × x - 2 + 16

g(x) = x^3 + 3x - 14/ x - 2

Hence, g(x) = (x^3 + 3x - 14)/ (x - 2)

Answer 2

Answer:

Step-by-step explanation:

Divisor*Quotient+Remainder= Divident

g(x)(x-2)+(-2x+4)=x3-3x2+x+2

g(x)(x-2)=x3-3x2+x+2+2x-4

g(x)(x-2)=x3-3x2+3x-2

g(x)=x3-3x2+3x-2/(x-2)

g(x)=x²-x+1