On dividing x^4-x^3-3x^2+3x+2find g(X) if q is x2 -x-2 and remainder is 2x
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Answered by
0
Step-by-step explanation:
let f(x)=x^4-x^3-3x^2+3x+2
use formula dividend = divisor × quotient + remainder
u get g(X)
Answered by
0
Answer:
hlo
Step-by-step explanation:
p(X)=q(X) G(X)+r(X)
x^4-x^3-3x^2+3x+2=(x2-x-2)g(X)+2x
x4-x3-3x2+3x+2-2x=(x2-x-2)g(X)
x4-x3-3x2+X+2/x2-x-2=g(X)
Therefore,g(X)= x2-1
hope it helps...
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