Question

On dividing x^(6)+5x^(3)+7x+3 by a polynomial g(x) the quotient and remainder wer 4^(4)-2x^(2)+5x+4 and -3x-5 respectively.Find g(x) .

Answer 1

Answer:

dividend = x^6+3x^3+7x+3

quotient = 4x^4-2x^2+5x+4

remainder = -3x-5

by remainder theorem

p(x)=g(x)× q+ r

a=bq+r

x^6+5x^3+7x+3=b×4x^4-2x^2+5x+4+(-3x-5)

-3x-5

x^6+5x^3+7x+3-(-3x-5)=b×4x^4-2x^2+5x+4

x^6+5x^3+7x+3+3x+5 =b

_______________

4x^4-2x^2+5x+4

x^6+5x^3+10x+8 = b

____________

4x^4-2x^2+5x+4

on dividing

please divide it alone it is not so tough

on dividing the answer is = b= g(x)

there is also some mistake in question

in quotient = 4x^4