Question

on dividing x3+3x+2 by a polynomial g(x) the quotient and remainder are x-2 and 16 respectively find g(x)

Answer 1

Step-by-step explanation:

this is the required answer

Answer 2

Answer:

Therefore value of g(x) is

$g(x) = {x}^{2} + 2x + 7$

Step-by-step explanation:

Dividend = Divisor × Quotient + Remainder

Here

Given

${x}^{3} + 3x + 2 = g(x)(x - 2) + 16$

we have to find g(x) Here

so

$g(x)(x - 2) = {x}^{3} + 3x - 14$

$g(x) = \frac{{x}^{3} + 3x - 14}{x - 2} [/$

$g(x) = \frac{(x - 2)( {x}^{2} + 2x + 7)}{x - 2}$

$g(x) = {x}^{2} + 2x + 7$

Therefore value of g(x) is

$g(x) = {x}^{2} + 2x + 7$

#SPJ3