On dividing x3 + 3x2 + 3x + 1 by x+ ߨ we get remainder
ߨ - (a
3 + 3 ߨ
2
- 3 ߨ + 1 b) ߨ
3 + 3 ߨ
2 + 3 ߨ + 1 c) - ߨ
3
ߨ 3-
2
- 3 ߨ- 1 d) −ߨ
3
ߨ 3-
2 + 3 ߨ + 1
Answers
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0
Answer:
indont know bro sorry please
Answered by
0
−π
3
+ 3π
2
− 3π+ 1
The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial ,
x−
a
, the remainder of that division will be equivalent to
f(a)
.
Given:
f(x)=
x 3
3x
2
+
3x+
1
f(x)is divided by a linear polynomial ,
x+
π
, the remainder of that division will be equivalent to
f(−π)
.
Remainder
=
f(−π)=
(−π) 3
3
(−π)
2
+
3(−π)+
1=
−π
3
+
3π
2
−
3π+
1
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