on dividing x³-3x²+x+2 by a polinomial g(x),the quotient and remainder were x-2 and -2x+4, respectively. findg(x)
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f(x)=g(x)×q(x)+r(x)
x^3-3x^2+x+2=g(x)×(x-2)+(-2x+4)
x^3-3x^2+x+2=g(x)×(x-2)+2x-4
x^3-3x^2+x+2-2x+4=g(x)×(x-2)
(x^3-3x^2-x+6)/(x-2) = g(x)
Solve it and get your answer
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