On dividing x³-3x²+x+2 by a polynomial g (x) ,the quotent and remainder were (x-2) and (-2x-4) respectively find g(x)
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Answer:
x² - x + 1
Step-by-step explanation:
On dividing x³-3x²+x+2 by a polynomial g (x) ,the quotent and remainder were (x-2) and (-2x+4) respectively find g(x)
f(x) = g(x)q(x) + r(x)
f(x) = x³-3x²+x+2
q(x) = x - 2
r(x) = -2x + 4
let say g(x) = (ax² + bx + c)
g(x)q(x) + r(x)
= (ax² + bx + c)(x - 2) + (-2x - 4)
= ax³ - (2a - b)x² + (c -2b)x -2c -2x +4
= ax³ - (2a - b)x² + (c -2b-2)x - 2c + 4
Comparing with
x³-3x²+x+2
a = 1
2a - b = 3 => b = -1
c - 2b - 2 = 1
=> c +2 - 2 = 1
=> c = 1
g(x) = (x² - x + 1)
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Quotient :- x²+x-5
Remainder :- x-2.
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