on dividing x3-3x2+x+2 by a polynomial g(x) the quotient and remainder were x-2 and-2x+4 resptively. find g(x)
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Answer:
Step-by-step explanation:
P(x)=g(x)q(x)+r(x)
x3-3x2+x+2=g(x)(x-2)+2x-4
x^3-3x^2-x+6=g(x)(x-2)
x^2-x-3=g(x)
Therefore,g(x)=x^2-x-3
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