Question

on dividing x3-3x2+x+2 by a polynomial g(x) the quotient and remainder were x-4 and 6 respectively find g(x)

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Answer 1

Answer:

Step-by-step explanation:

Dividend=x^3-3x^2+x+2

divisor=g(x)

quotient=(x-4)

remainder=6

x^3-3x^2+x+2=g(x)(x-4)(6)

x^3-3x^2+x+2-6=g(x)(x-4)

x^3-3x^2+x-4=g(x)(x-4)

g( x)=x^2+x+5

Answer 2

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Hope it helps.............