On dividing x3
-3x2+x+2 by a polynomial g(x), the quotient and remainder
were x-2 and -2x+4 respectively. Find g(x).
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Answer:
Given
f(x)=x
3
+5x
2
−ax+6
Let us assume
x−1=0⇒x=1
By remainder theorem, when f(x) is divide by (x−1),
Remainder r=f(1)
⇒2a=(1)
3
+5(1)
2
−a(1)+6[∵r=2a(Given)]
⇒2a=1+5−a+6
⇒2a+a=12
⇒3a=12
⇒a=
3
12
⇒a=4
Therefore, the value of a is 4.
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