On dividing x3
-3x2
+x+2 by a polynomial g(x), the quotient and remainder were
x-2 and -2x+4 respectively. Find g(x).
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x^3-3x^2+x+2-(-2x+4)=g(x)×(x-2)
x^3-3x^2+x+2+4x-8=g(x)×(x-2)
x^3-3x^2+5x-6=g(x)×(x-2)
x^3-3x^2+5x-6/x-2=g(x)
x^2+x+7=g(x)
x^3-3x^2+x+2+4x-8=g(x)×(x-2)
x^3-3x^2+5x-6=g(x)×(x-2)
x^3-3x^2+5x-6/x-2=g(x)
x^2+x+7=g(x)
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