On dividing x3- 5x2+6x+4 by a polynomial g(x) the quotient and the remainder were x-3 and 4. Find g(x)
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Using Division algorithm,
p(x) = q(x) × g(x) + r(x)
Then,
x³-5x²+6x+4 = (x-3) × g(x) + 4
x³-5x²+6x+4-4 = (x-3) × g(x)
g(x) = (x³-5x²+6x) / (x-3)
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On, Dividing g(x) = x²-2x
Hence g(x) = x²-2x (or) x²-2x+0
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☺☺☺ Hope this Helps ☺☺☺
p(x) = q(x) × g(x) + r(x)
Then,
x³-5x²+6x+4 = (x-3) × g(x) + 4
x³-5x²+6x+4-4 = (x-3) × g(x)
g(x) = (x³-5x²+6x) / (x-3)
________________________________________________________
On, Dividing g(x) = x²-2x
Hence g(x) = x²-2x (or) x²-2x+0
________________________________________________________
☺☺☺ Hope this Helps ☺☺☺
sharanyagacharya:
Tq...very much...i have more doubts ,,, i u pls ans
Yes for sure
If alpha and beta are 0's of the polynomial x2 -x-k such that alpha -beta is 9 .Find k
We know that alpha + beta = -b/a and so = -(1)/1 = 1 then solve alpha + beta = 1 and alpha - beta = 9 u get the value of alpha and beta then substituting any of them in the polynomial = 0 u get the value of k.
If u ask in the ques column it would be helpful for u as I can explain it well and u also get two answers
Can u pls ans .....
ask in ques column I'm waiting
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