On dividing x3 – 6x2 + 11x – 6 by a polynomial g(x), the quotient and the remainder were x2 – 8x + 27 and – 60 respectively. Find g(x).
Answers
Step-by-step explanation:
answer to this question☝
Given : On dividing x3 – 6x2 + 11x – 6 by a polynomial g(x), the quotient and the remainder were x2 – 8x + 27 and – 60 respectively
To Find : g(x).
Solution:
a = bq + r
x³ - 6x² + 11x - 6 = g(x) ( x² - 8x + 27) + (-60)
=> x³ - 6x² + 11x + 54 = g(x) ( x² - 8x + 27)
=> g(x) = (x³ - 6x² + 11x + 54 ) / ( x² - 8x + 27)
x + 2
( x² - 8x + 27) _| (x³ - 6x² + 11x + 54 ) |_
x³ - 8x² +27x
____________
2x² - 16x + 54
2x² - 16x + 54
_____________
0
Quotient is x + 2
Learn More:
on dividing x3-3x2+x+2 by a polynomial g(x),the quotient and ...
brainly.in/question/3135153
Divide 9x^3+3x^2-5x+7 by (3x-1) write the quotient and remainder ...
brainly.in/question/6190809
Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1 ...
brainly.in/question/4743553