Question

on dividing y ^ 3-3y^2+4y-5 by y-2 the quotient and​

Answer 1

Answer:

${y}^{3} - 3 {y}^{2} + 4y - 5 = \\ {y}^{3} - 2 {y}^{2} - {y}^{2} + 2y + 2y - 4 - 1 = \\ {y}^{2} (y - 2) - y(y - 2) + 2(y - 2) - 1 = \\ (y - 2)( {y}^{2} - y + 2) - 1$

so Quotient = y² – y + 2

Reminder = –1