on diving a positive integer n by 9 we get 7 as remainder remainder will be 3n-1 is divided by 9
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answer of this question is two
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Sol: Given A positive integer n is divided by 9 gives 7 as the remainder. Let a be quotient n = 9a+7 3n-1 is divided by 9 now, 3n-1= 3(9a+7)-1 =27a + 21-1 =27a +20 = 27 a + 18 + 2 = 9( 3a + 6) + 2 when divided by 9 Remainder = 2.
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