Question

On Diwali eve, two candles, one of which is 3 cm longer than the other are

lighted. The longer one is lighted at 5.30 p.m. and the shorter at 7 p.m. At

9.30p.m. they both are of the same length. The longer one burns out at

11.30p.m. and the shorter one at 11 p.m. How long was each candle

originally?

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Answer 1

hello!!!

x and x + 3 are the lengths

x + 3 was lit at 3:30

at 7:30, it was the same length as the other candle (4 hours)

(x + 3) - 4 * k = x - 2.5 * m

After 6 hours, the longer candle burned out

x + 3 - 6k = 0

After 4 hours, the shorter candle burned out

x - 4m = 0

x + 3 = 6k

k = (x + 3) / 6

x - 4m = 0

x = 4m

x/4 = m

(x + 3) - 4 * k = x - 2.5 * m

(x + 3) - 4 * (x + 3) / 6 = x - (5/2) * (x/4)

(x + 3) * (1 - 2/3) = x * (1 - 5/8)

(x + 3) * (1/3) = x * (3/8)

x/3 + 1 = 3x/8

1 = 3x/8 - x/3

1 = 9x/24 - 8x/24

1 = x/24

24 = x

24 cm and 27 cm

hope it helps u❤️❤️

____________________

mark as brainliest

Answer 2

Answer:

I don't know do your self