Question

On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension? 

Answer 1

Answer:

Mass = 18.0 kg

Explanation:

From Hooke's law,

F = ke

where: F is the force, k is the spring constant and e is the extension.

But, F = mg

So that,

mg = ke

On the Earth, let the gravitational force be 10 m/.

3.0 x 10 = k x 5.0

30 = 5k

⇒ k =   1

On the Moon, the gravitational force is  of that on the Earth.

m x  = k x 5.0

 = 5k

⇒ k =  2

Equating 1 and 2, we have;

 m = 18.0 kg

The mass required to produce the same extension on the Moon is 18 kg.

I hope this explanation was clear

Thank you